What were the dimensions of Nebuchadnezzar's golden image?
The golden image was sixty cubits high and six cubits wide. Using the stated cubit measure of a foot and a half, that equals about ninety feet tall and about nine feet wide. It was set out on Middle Eastern desert sands, and he demanded his whole then-known world worship it.
Les explains that chapter 3 follows the dream of chapter 2, where the image had only a head of gold. Nebuchadnezzar had forgotten what Daniel had said, and he became so filled with his own power and self that he wanted to unite all those pagan religions into worship of one image, which would be of himself. He made an image of gold whose height was three score, or 60 cubits, and its width was 6 cubits. Since a cubit is a foot and a half, that is 90 feet high and about 9 feet wide. Les calls it a pretty good size image, set out on the Middle Eastern desert sands, and Nebuchadnezzar demanded that his whole then-known world worship that image. Les also ties this to the last great world ruler, the Antichrist, who will do the same thing.
Nebuchadnezzar the king made an image of gold, whose height was threescore cubits, and the breadth thereof six cubits: he set it up in the plain of Dura, in the province of Babylon.
More Questions
How large was Nebuchadnezzar's golden image in Daniel 3?
Nebuchadnezzar's golden image was about 90 feet high (60 cubits) and about 9 feet wide (6 cubits), so it was a huge image.